Area of Triangles and Quadrilaterals
Grade 7 · Math · Geometry · Montana, USA
Lesson Summary
Calculate the area of triangles, parallelograms, trapezoids, and other four-sided shapes.
Explanation
The area of a triangle is A = ½ × base × height. For a parallelogram, A = base × height (the height must be perpendicular to the base, not a slanted side). For a trapezoid, A = ½(b₁ + b₂) × h, where b₁ and b₂ are the two parallel sides. Knowing these formulas lets you calculate the space covered by many common shapes.
Practice Questions
Q1: Find the area of a triangle with base 10 cm and height 6 cm.
Answer: A = ½ × 10 × 6 = 30 cm².
Q2: Find the area of a parallelogram with base 8 in. and height 5 in.
Answer: A = 8 × 5 = 40 in².
Q3: Find the area of a trapezoid with bases 7 m and 11 m and height 4 m.
Answer: A = ½(7 + 11) × 4 = ½ × 18 × 4 = 36 m².
People Also Ask
What is Area of Triangles and Quadrilaterals in Grade 7 Math?+
Area of Triangles and Quadrilaterals is a lesson in the Geometry chapter of Grade 7 Math. It is part of the Montana, USA school curriculum and covers key concepts that students need to understand at this level.
What grade level covers Area of Triangles and Quadrilaterals?+
Area of Triangles and Quadrilaterals is taught in Grade 7 as part of the Math curriculum in Montana, USA.
How can I help my child with Geometry in Math?+
Start with the lesson summary and explanation on this page. Practice the questions provided, then use TutorTom for personalized, step-by-step help with Geometry topics.